如下：
select regexp_substr('bbb,aaa,ccc', '[^,]+', 1, level) as split_result
from dual
connect by level <=
length('bbb,aaa,ccc') - length(replace('bbb,aaa,ccc', ',')) + 1;
如下：
select regexp_substr(replace('aaa;bbb;ccb', '', ';'), '[^;]+', 1, level) as split_result
from dual
connect by level <= regexp_count('aaa;bb;', ';') + 1;
或者 with 写法，如下
with temp as (select 'bbb,aaa,ccc' as str from dual) select regexp_substr(replace(str, ',', ' ,'), '[^,]+', 1, level) from temp connect by level <= regexp_count(str, ',') + 1
问题情况（可能会出现空行），如下：
解决问题：
上述空行不是我们所需要的，所以排除即可，如下：
select split_result,length(split_result) from (
select regexp_substr(replace('aaa;bb;', '', ';'), '[^;]+', 1, level) as split_result
from dual
connect by level <= regexp_count('aaa;bb;', ';') + 1)
where split_result is not null;
如下：
create or replace type result_split_list as table of varchar2(100);
如下：
create or replace function split_strs(strs varchar2, type_split varchar2)
return result_split_list
pipelined is
index_num pls_integer;
str_list varchar2(100) := strs;
begin
loop
index_num := instr(str_list, type_split);
if index_num > 0 then
pipe row(substr(str_list, 1, index_num - 1));
str_list := substr(str_list, index_num + length(type_split));
else
pipe row(str_list);
exit;
end if;
end loop;
return;
end split_strs;
如下：
上面的效果我们看到查看到的是＜Collection＞ 类型，不方便查看数据，处理如下：
select * from table (select split_strs('aaa,bbb,ccc',',') from dual);
