DevExpress实现TreeList向上递归获取符合条件的父节点 DevExpress实现TreeList向上递归获取符合条件的父节点

/// <summary>
/// 向上递归，获取符合条件的父节点
/// </summary>
/// <param name="node">需要向上递归的节点</param>
/// <param name="conditionHanlder">判断条件【委托】</param>
/// <returns>符合条件的节点【TreeListNode】</returns>
public static TreeListNode GetParentNode(this TreeListNode node, Predicate<TreeListNode> conditionHanlder)
{
  TreeListNode _parentNode = node.ParentNode;//获取上一级父节点
  TreeListNode _conditonNode = null;
  if (_parentNode != null)
  {
 if (conditionHanlder(_parentNode))//判断上一级父节点是否符合要求
 {
   _conditonNode = _parentNode;
 }
 if (_conditonNode == null)//若没有找到符合要求的节点，递归继续
   _conditonNode = GetParentNode(_parentNode, conditionHanlder);
  }
  return _conditonNode;
}

TreeListNode _node = e.Node;
TreeListNode _condionParent = _node.GetParentNode(n => n.GetNodeType() == NodeType.Cab);//获取类型为CAB类型的父节点
Trace.WriteLine(_condionParent.GetName());