本文实例讲述了Go语言通过smtp发送邮件的方法。分享给大家供大家参考。具体实现方法如下：
/*
* user : example@example.com login smtp server user
* password: xxxxx login smtp server password
* host: smtp.example.com:port smtp.163.com:25
* to: example@example.com;example1@163.com;example2@sina.com.cn;...
* subject:The subject of mail
* body: The content of mail
* mailtyoe: mail type html or text
*/
func SendMail(user, password, host, to, subject, body, mailtype string) error{
hp := strings.Split(host, ":")
auth := smtp.PlainAuth("", user, password, hp[0])
var content_type string
if mailtype == "html" {
content_type = "Content-Type: text/"+ mailtype + "; charset=UTF-8"
}else{
content_type = "Content-Type: text/plain" + "; charset=UTF-8"
}
msg := []byte("To: " + to + "\r\nFrom: " + user + "<"+ user +">\r\nSubject: " + subject + "\r\n" + content_type + "\r\n\r\n" + body)
send_to := strings.Split(to, ";")
err := smtp.SendMail(host, auth, user, send_to, msg)
return err
}
func main() {
user := "xxxx@163.com"
password := "xxxx"
host := "smtp.163.com:25"
to := "xxxx@gmail.com;ssssss@gmail.com"
subject := "Test send email by golang"
body := `
<html>
<body>
<h3>
"Test send email by golang"
</h3>
</body>
</html>
`
fmt.Println("send email")
err := SendMail(user, password, host, to, subject, body, "html")
if err != nil {
fmt.Println("send mail error!")
fmt.Println(err)
}else{
fmt.Println("send mail success!")
}
}
希望本文所述对大家的Go语言程序设计有所帮助。
