本文实例讲述了php检测mysql表是否存在的方法。分享给大家供大家参考，具体如下：
pdo:
<?php
$dsn = 'mysql:dbname=test;host=127.0.0.1';
$user = 'root';
$password = '';
try {
$pdo = new PDO($dsn, $user, $password);
} catch (PDOException $e) {
die("数据库连接失败".$e->getMessage());
}
$table = 'cy_news';
//判断表是否存在
$result = $pdo->query("SHOW TABLES LIKE '". $table."'");
$row = $result->fetchAll();
if('1' == count($row)){
echo "Table exists";
} else {
echo "Table does not exist";
}
?>
mysql:
<?php
$con = mysql_connect("localhost","root","");
mysql_select_db("php_cms", $con);
$table = 'cy_news';
if(mysql_num_rows(mysql_query("SHOW TABLES LIKE '". $table."'"))==1) {
echo "Table exists";
} else {
echo "Table does not exist";
}
?>
希望本文所述对大家PHP程序设计有所帮助。
