大家应该都知道，银行打印账单有时候会跟上人民币的阿拉伯数字以及人民币汉字大写写法，转换的过程中有一定的逻辑难度，较为麻烦，所以笔者心血来潮，花了点时间简单实现了一下这一转换过程，以供初学者参考。
输入样例：
123.22
输出样例：
壹佰贰拾叁圆贰角贰分
参考代码：
#!/usr/bin/env python
# encoding: utf-8
from __future__ import print_function
import sys
import re
import base64
import time
import os
import getpass
reload(sys)
sys.setdefaultencoding("utf-8")
char_arr_01 = [u"零".decode("utf8"), u"壹".decode("utf8"), u"贰".decode("utf8"), u"叁".decode("utf8"), u"肆".decode(
"utf8"), u"伍".decode("utf8"), u"陆".decode("utf8"), u"柒".decode("utf8"), u"捌".decode("utf8"), u"玖".decode("utf8")];
char_arr_02 = [u"圆".decode("utf8"), u"拾".decode("utf8"), u"佰".decode("utf8"), u"仟".decode("utf8"), u"万".decode("utf8"), u"拾".decode("utf8"), u"佰".decode("utf8"), u"仟".decode(
"utf8"), u"亿".decode("utf8"), u"拾".decode("utf8"), u"佰".decode("utf8"), u"仟".decode("utf8"), u"万".decode("utf8"), u"拾".decode("utf8"), u"佰".decode("utf8")]
char_arr_03 = [u"分".decode("utf8"), u"角".decode("utf8")]
def calcRMB():
sum_arr = []
in_str_dot = ""
in_str_Big = ""
flag = 0
dot_count = 0
in_str = raw_input("Please input number : ")
for i in in_str:
if i == '.':
dot_count += 1
elif ord(i) <= ord('z') and ord(i) >= ord('A'):
print("Error")
return
if len(in_str) > 12 or dot_count > 1:
print("Error")
return
in_str = unicode(in_str).decode("utf8")
out_str = ""
if in_str.find('.') != -1:
flag = 1
sum_arr = in_str.split('.')
in_str_Big = sum_arr[0]
if flag==1:
in_str_dot = sum_arr[1]
for i in range(len(in_str_Big)):
if cmp(in_str_Big[i],'0') == 0 and (len(in_str_Big)-1-i)%4 != 0:
out_str = out_str + char_arr_01[ord(in_str_Big[i])-ord('0')]
else:
out_str = out_str + char_arr_01[ord(in_str_Big[i])-ord('0')]
out_str = out_str + char_arr_02[len(in_str_Big)-1-i]
while out_str.find(u"零零".decode("utf8")) != -1:
out_str = out_str.replace(u"零零".decode("utf8"), u"零".decode("utf8"))
out_str = out_str.replace(u"零亿".decode("utf8"),u"亿".decode("utf8"))
out_str = out_str.replace(u"零万".decode("utf8"),u"万".decode("utf8"))
if out_str != u"零元".decode("utf8"):
out_str = out_str.replace(u"零圆".decode("utf8"),u"圆".decode("utf8"))
if len(in_str_dot) > 2 and flag == 1:
print("False !!")
return
if flag == 1:
for i in range(len(in_str_dot)):
out_str = out_str + char_arr_01[ord(in_str_dot[i])-ord('0')]
out_str = out_str + char_arr_03[len(in_str_dot)-1-i]
print(out_str)
def main():
while 1:
os.system("cls")
calcRMB()
print()
end_flag = raw_input("Try Again ? (y/n)")
if end_flag == 'y' or end_flag == 'Y':
continue
elif end_flag == 'n' or end_flag == 'N':
break
else:
print("\nError!!")
break
if __name__ == '__main__':
main()
