C# 获取当前年份的周期周期所在日期范围 C# 获取当前年份的周期及周期所在日期范围(推荐)

using System;
using System.Collections.Generic;
using System.Globalization;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
namespace ConsoleApplication6
{
  class Program
  {
    static void Main(string[] args)
    {
      GregorianCalendar gc = new GregorianCalendar();
      int weekOfYear = gc.GetWeekOfYear(DateTime.Now, CalendarWeekRule.FirstDay, DayOfWeek.Monday);
      Console.WriteLine("当前第{0}周", weekOfYear);
      DateTime startDate, lastDate;
      for (int i = 1; i <= 53; i++)
      {
        GetDaysOfWeeks(DateTime.Now.Year, i, out startDate, out lastDate);
        Console.WriteLine("第{0}周", i);
        Console.WriteLine(startDate);
        Console.WriteLine(lastDate);
      }
      Console.ReadLine();
    }
    public static bool GetDaysOfWeeks(int year, int index, out DateTime first, out DateTime last)
    {
      first = DateTime.MinValue;
      last = DateTime.MinValue;
      if (year < 1700 || year > 9999)
      {
        //"年份超限"
        return false;
      }
      if (index < 1 || index > 53)
      {
        //"周数错误"
        return false;
      }
      DateTime startDay = new DateTime(year, 1, 1); //该年第一天
      DateTime endDay = new DateTime(year + 1, 1, 1).AddMilliseconds(-1);
      int dayOfWeek = 0;
      if (Convert.ToInt32(startDay.DayOfWeek.ToString("d")) > 0)
        dayOfWeek = Convert.ToInt32(startDay.DayOfWeek.ToString("d")); //该年第一天为星期几
      if (dayOfWeek == 0) { dayOfWeek = 7; }
      if (index == 1)
      {
        first = startDay.AddDays(7 - dayOfWeek - 6);
        if (dayOfWeek == 6)
        {
          last = first;
        }
        else
        {
          last = startDay.AddDays((7 - dayOfWeek));
        }
      }
      else
      {
        first = startDay.AddDays((8 - dayOfWeek) + (index - 2) * 7); //index周的起始日期
        last = first.AddDays(6);
        //if (last > endDay)
        //{
        //  last = endDay;
        //}
      }
      if (first > endDay) //startDayOfWeeks不在该年范围内
      {
        //"输入周数大于本年最大周数";
        return false;
      }
      return true;
    }
  }
}