一、构建棋盘
首先可以用一个二维数组来构建棋盘，下标表示位置，内容表示黑子白子或者空位。当数组内容为1时，该位置为白字，当数组为0时，该位置为白子，空位输出+
int w[11][11], flag = 0;
int a, b;
for (int k = 0; k < 11; k++)
printf("第%d列\t", k);
printf("\n");
for (int i = 0; i < 11; i++) {
for (int j = 0; j < 11; j++) {
if (w[i][j] == 0) printf("黑\t");
else if (w[i][j] == 1) printf("白\t");
else printf("+\t");
}
printf("第%d行\n\n", i);
}
二、判断位置超范围与错误输入
当输入的棋子坐标超出范围或者该位置已经存在棋子，则再次输入棋子坐标。其中flag作为标志作为判别黑手白手的标志。
if (flag == 0) {
printf("黑色下棋\n");
scanf("%d %d", &a, &b);
while (a < 0 || a>10 || b < 0 || b>10) {
printf("此位置超出范围，请重新输入：");
scanf("%d %d", &a, &b);
}
while (w[a][b] == 0 || w[a][b] == 1)
{
printf("此位置已有棋子，请重新输入：");
scanf("%d %d", &a, &b);
}
flag = 1;
w[a][b] = 0;
}
else {
printf("白色下棋\n");
scanf("%d %d", &a, &b);
while (a < 0 || a>10 || b < 0 || b>10) {
printf("此位置超出范围，请重新输入：");
scanf("%d %d", &a, &b);
}
while (w[a][b] == 0 || w[a][b] == 1)
{
printf("此位置已有棋子，请重新输入：");
scanf("%d %d", &a, &b);
}
三、判断胜负
在五子棋中，出现五个棋子排成一排或者一列或者斜排即可判为胜出。每当落下一个棋子，对该棋子前后上下斜排五个棋子进行判别，超过五个连续的一样颜色的棋子则胜出。
int A = 1, B = 1, jieguo = 0, C = 1, D = 1;
int x = 1, y = 1, m = 1, n = 1;
if (w[a][b] == 1) {
for (int i = 1; i < 5; i++) {
if (w[a][b + i] == 1) A++;
else break;
}
for (int i = 1; i < 5; i++) {
if (w[a][b - i] == 1) A++;
else break;
}
for (int i = 1; i < 5; i++)
{
if (w[a+i][b] == 1) C++;
else break;
}
for (int i = 1; i < 5; i++)
{
if (w[a - i][b] == 1) C++;
else break;
}
if (A > 4 || C > 4) jieguo = 1;//白棋胜利标志
else {
for (int i = 1; i < 5; i++) {
if (w[a+i][b + i] == 1) x++;
else break;
}
for (int i = 1; i < 5; i++) {
if (w[a-i][b - i] == 1) x++;
else break;
}
for (int i = 1; i < 5; i++)
{
if (w[a + i][b-i] == 1) y++;
else break;
}
for (int i = 1; i < 5; i++)
{
if (w[a - i][b+i] == 1) y++;
else break;
}
if (x > 4 || y > 4) jieguo = 1;
}
}
if (w[a][b] == 0) {
for (int i = 1; i < 5; i++) {
if (w[a][b + i] == 0) B++;
else break;
}
for (int i = 1; i < 5; i++) {
if (w[a][b - i] == 0) B++;
else break;
}
for (int i = 1; i < 5; i++)
{
if (w[a + i][b] == 0) D++;
else break;
}
for (int i = 1; i < 5; i++)
{
if (w[a - i][b] == 0) D++;
else break;
}
if (B > 4 || D > 4) jieguo = 2;//黑棋胜利标志
else {
for (int i = 1; i < 5; i++) {
if (w[a + i][b + i] == 0) m++;
else break;
}
for (int i = 1; i < 5; i++) {
if (w[a - i][b - i] == 0) m++;
else break;
}
for (int i = 1; i < 5; i++)
{
if (w[a + i][b - i] == 0) n++;
else break;
}
for (int i = 1; i < 5; i++)
{
if (w[a - i][b + i] == 0) n++;
else break;
}
if (m > 4 || n > 4) jieguo = 2;
}
}
程序完成
四、演示结果
五、源代码
int main() {
int w[11][11], flag = 0;
int a, b;
while (1) {
if (flag == 0) {
printf("黑色下棋\n");
scanf("%d %d", &a, &b);
while (a < 0 || a>10 || b < 0 || b>10) {
printf("此位置超出范围，请重新输入：");
scanf("%d %d", &a, &b);
}
while (w[a][b] == 0 || w[a][b] == 1)
{
printf("此位置已有棋子，请重新输入：");
scanf("%d %d", &a, &b);
}
flag = 1;
w[a][b] = 0;
}
else {
printf("白色下棋\n");
scanf("%d %d", &a, &b);
while (a < 0 || a>10 || b < 0 || b>10) {
printf("此位置超出范围，请重新输入：");
scanf("%d %d", &a, &b);
}
while (w[a][b] == 0 || w[a][b] == 1)
{
printf("此位置已有棋子，请重新输入：");
scanf("%d %d", &a, &b);
}
flag = 0;
w[a][b] = 1;
}
int A = 1, B = 1, jieguo = 0, C = 1, D = 1;
int x = 1, y = 1, m = 1, n = 1;
if (w[a][b] == 1) {
for (int i = 1; i < 5; i++) {
if (w[a][b + i] == 1) A++;
else break;
}
for (int i = 1; i < 5; i++) {
if (w[a][b - i] == 1) A++;
else break;
}
for (int i = 1; i < 5; i++)
{
if (w[a+i][b] == 1) C++;
else break;
}
for (int i = 1; i < 5; i++)
{
if (w[a - i][b] == 1) C++;
else break;
}
if (A > 4 || C > 4) jieguo = 1;//白棋胜利标志
else {
for (int i = 1; i < 5; i++) {
if (w[a+i][b + i] == 1) x++;
else break;
}
for (int i = 1; i < 5; i++) {
if (w[a-i][b - i] == 1) x++;
else break;
}
for (int i = 1; i < 5; i++)
{
if (w[a + i][b-i] == 1) y++;
else break;
}
for (int i = 1; i < 5; i++)
{
if (w[a - i][b+i] == 1) y++;
else break;
}
if (x > 4 || y > 4) jieguo = 1;
}
}
if (w[a][b] == 0) {
for (int i = 1; i < 5; i++) {
if (w[a][b + i] == 0) B++;
else break;
}
for (int i = 1; i < 5; i++) {
if (w[a][b - i] == 0) B++;
else break;
}
for (int i = 1; i < 5; i++)
{
if (w[a + i][b] == 0) D++;
else break;
}
for (int i = 1; i < 5; i++)
{
if (w[a - i][b] == 0) D++;
else break;
}
if (B > 4 || D > 4) jieguo = 2;//黑棋胜利标志
else {
for (int i = 1; i < 5; i++) {
if (w[a + i][b + i] == 0) m++;
else break;
}
for (int i = 1; i < 5; i++) {
if (w[a - i][b - i] == 0) m++;
else break;
}
for (int i = 1; i < 5; i++)
{
if (w[a + i][b - i] == 0) n++;
else break;
}
for (int i = 1; i < 5; i++)
{
if (w[a - i][b + i] == 0) n++;
else break;
}
if (m > 4 || n > 4) jieguo = 2;
}
}
for (int k = 0; k < 11; k++)
printf("第%d列\t", k);
printf("\n");
for (int i = 0; i < 11; i++) {
for (int j = 0; j < 11; j++) {
if (w[i][j] == 0) printf("黑\t");
else if (w[i][j] == 1) printf("白\t");
else printf("+\t");
}
printf("第%d行\n\n", i);
}
if (jieguo == 1) {
printf("白棋胜利");
break;
}
if (jieguo == 2) {
printf("黑棋胜利");
break;
}
}
return 0;
}
