编写一个名为printTable()的函数，它接受字符串的列表的列表，将它显示在组织良好的表格中，每列右对齐。假定所有内层列表都包含同样数目的字符串。例如，该值可能看起来像这样：
table_data = [['apples', 'oranges', 'cherries', 'banana'],
['Alice', 'Bob', 'Carol', 'David'],
['dogs', 'cats', 'moose', 'goose']]
你的 printTable()函数将打印出：
apples Alice dogs oranges Bob cats cherries Carol moose banana David goose
示例代码1：
import copy
def count_width(the_list):
new_list = copy.deepcopy(the_list)
col_widths = [0]*len(the_list)
i = 0
while i < len(new_list):
new_list[i].sort(key=lambda x: len(x), reverse=True)
col_widths[i] = new_list[i][0]
i = i+1
return col_widths
def list_ljust(the_list):
widths = count_width(the_list)
for j in range(len(the_list[0])):
for i in range(len(the_list)):
print(the_list[i][j].ljust(len(widths[i])), end=' ')
print('\r')
table_data = [['apples', 'oranges', 'cherries', 'banana'],
['Alice', 'Bob', 'Carol', 'David'],
['dogs', 'cats', 'moose', 'goose']]
list_ljust(table_data)
sort方法：
lambda函数：
示例代码2：
def count_widths(the_list):
col_widths = [0]*len(the_list)
for i in range(len(the_list)):
for j in range(len(the_list[0])):
if len(the_list[i][j]) > max_len:
max_len = len(the_list[i][j])
col_widths[i] = max_len
return col_widths
def list_ljust(the_list):
widths = count_widths(the_list)
print(widths)
for j in range(len(the_list[0])):
for i in range(len(the_list)):
print(the_list[i][j].ljust(widths[i]), end=' ')
print('\r')
table_data = [['apples', 'oranges', 'cherries', 'banana'],
['Alice', 'Bob', 'Carol', 'David'],
['dogs', 'cats', 'moose', 'goose']]
list_ljust(table_data)
