执行大型js时有点慢
特殊编码的输入或输出参数会出现报错，解决方法：
可以把输入或输出的参数用base64编码一下。base64都是英文和数字，没有特殊字符了
pip insatll js2py
# 获取执行JS的环境
context = js2py.EvalJs()
# 加载执行
context.execute('放JS字符代码')
import execjs print(execjs.get().name) # Node.js (V8)
import execjs
user_id = '3232597584'
url = f'https://www.toutiao.com/toutiao/api/pc/feed/?min_behot_time=1588149898&category=__all__&utm_source=toutiao&widen=1&tadrequire=true&user_id={user_id}&visited_uid={user_id}'
js_index = """
js
"""
# 打开js文件读取
# new_url = execjs.compile(open("/Users/ts/Desktop/Jeff/今日头条/new_sign.js").read()).call('get_sigtrue', url)
# 读取js字符串
new_url = execjs.compile(js_index).call('get_sigtrue', url)
print(new_url)
import execjs
def get_js():
f = open("./new_sign.js", 'r', encoding = 'UTF-8')
line = f.readline()
htmlstr = ''
while line:
htmlstr = htmlstr + line
line = f.readline()
return htmlstr
jsstr = get_js()
ctx = execjs.compile(jsstr)
user_id = '3232597584'
url = f'https://www.toutiao.com/toutiao/api/pc/feed/?min_behot_time=1588149898&category=__all__&utm_source=toutiao&widen=1&tadrequire=true&user_id={user_id}&visited_uid={user_id}'
print(ctx.call('getUrl', url))
