jQuery获取某天的农历日期并判断是否除夕或新年的方法

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jQuery获取某天的农历日期并判断是否除夕或新年的方法

yenange   2020-05-15 我要评论

本文实例讲述了jQuery获取某天的农历日期并判断是否除夕或新年的方法。分享给大家供大家参考,具体如下:

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<script src="jquery.min.js" type="text/javascript"></script>
<script type="text/javascript">
  //------------------- Begin ----------------------
  CalendarHelper={};
  CalendarHelper.GetCNDate = function (D) {
    var CalendarData = new Array(100);
    var madd = new Array(12);
    var tgString = "甲乙丙丁戊己庚辛壬癸";
    var dzString = "子丑寅卯辰巳午未申酉戌亥";
    var numString = "一二三四五六七八九十";
    var monString = "正二三四五六七八九十冬腊";
    var weekString = "日一二三四五六";
    var sx = "鼠牛虎兔龙蛇马羊猴鸡狗猪";
    var cYear, cMonth, cDay, TheDate;
    CalendarData = new Array(0xA4B, 0x5164B, 0x6A5, 0x6D4, 0x415B5, 0x2B6, 0x957, 0x2092F, 0x497, 0x60C96, 0xD4A, 0xEA5, 0x50DA9, 0x5AD, 0x2B6, 0x3126E, 0x92E, 0x7192D, 0xC95, 0xD4A, 0x61B4A, 0xB55, 0x56A, 0x4155B, 0x25D, 0x92D, 0x2192B, 0xA95, 0x71695, 0x6CA, 0xB55, 0x50AB5, 0x4DA, 0xA5B, 0x30A57, 0x52B, 0x8152A, 0xE95, 0x6AA, 0x615AA, 0xAB5, 0x4B6, 0x414AE, 0xA57, 0x526, 0x31D26, 0xD95, 0x70B55, 0x56A, 0x96D, 0x5095D, 0x4AD, 0xA4D, 0x41A4D, 0xD25, 0x81AA5, 0xB54, 0xB6A, 0x612DA, 0x95B, 0x49B, 0x41497, 0xA4B, 0xA164B, 0x6A5, 0x6D4, 0x615B4, 0xAB6, 0x957, 0x5092F, 0x497, 0x64B, 0x30D4A, 0xEA5, 0x80D65, 0x5AC, 0xAB6, 0x5126D, 0x92E, 0xC96, 0x41A95, 0xD4A, 0xDA5, 0x20B55, 0x56A, 0x7155B, 0x25D, 0x92D, 0x5192B, 0xA95, 0xB4A, 0x416AA, 0xAD5, 0x90AB5, 0x4BA, 0xA5B, 0x60A57, 0x52B, 0xA93, 0x40E95);
    madd[0] = 0;
    madd[1] = 31;
    madd[2] = 59;
    madd[3] = 90;
    madd[4] = 120;
    madd[5] = 151;
    madd[6] = 181;
    madd[7] = 212;
    madd[8] = 243;
    madd[9] = 273;
    madd[10] = 304;
    madd[11] = 334;
    function GetBit(m, n) {
      return (m >> n) & 1;
    }
    function e2c() {
      TheDate = (arguments.length != 3) ? new Date() : new Date(arguments[0], arguments[1], arguments[2]);
      var total, m, n, k;
      var isEnd = false;
      var tmp = TheDate.getYear();
      if (tmp < 1900) {
        tmp += 1900;
      }
      total = (tmp - 1921) * 365 + Math.floor((tmp - 1921) / 4) + madd[TheDate.getMonth()] + TheDate.getDate() - 38;
      if (TheDate.getYear() % 4 == 0 && TheDate.getMonth() > 1) {
        total++;
      }
      for (m = 0; ; m++) {
        k = (CalendarData[m] < 0xfff) ? 11 : 12;
        for (n = k; n >= 0; n--) {
          if (total <= 29 + GetBit(CalendarData[m], n)) {
            isEnd = true; break;
          }
          total = total - 29 - GetBit(CalendarData[m], n);
        }
        if (isEnd) break;
      }
      cYear = 1921 + m;
      cMonth = k - n + 1;
      cDay = total;
      if (k == 12) {
        if (cMonth == Math.floor(CalendarData[m] / 0x10000) + 1) {
          cMonth = 1 - cMonth;
        }
        if (cMonth > Math.floor(CalendarData[m] / 0x10000) + 1) {
          cMonth--;
        }
      }
    }
    function GetcDateString() {
      var tmp = "";
      tmp += tgString.charAt((cYear - 4) % 10);
      tmp += dzString.charAt((cYear - 4) % 12);
      tmp += "(";
      tmp += sx.charAt((cYear - 4) % 12);
      tmp += ")年 ";
      if (cMonth < 1) {
        tmp += "(闰)";
        tmp += monString.charAt(-cMonth - 1);
      } else {
        tmp += monString.charAt(cMonth - 1);
      }
      tmp += "月";
      tmp += (cDay < 11) ? "初" : ((cDay < 20) ? "十" : ((cDay < 30) ? "廿" : "三十"));
      if (cDay % 10 != 0 || cDay == 10) {
        tmp += numString.charAt((cDay - 1) % 10);
      }
      return tmp;
    }
    function GetLunarDay(solarYear, solarMonth, solarDay) {
      //solarYear = solarYear<1900?(1900+solarYear):solarYear;
      if (solarYear < 1921 || solarYear > 2020) {
        return "";
      } else {
        solarMonth = (parseInt(solarMonth) > 0) ? (solarMonth - 1) : 11;
        e2c(solarYear, solarMonth, solarDay);
        return GetcDateString();
      }
    }
    var yy = D.getFullYear();
    var mm = D.getMonth() + 1;
    var dd = D.getDate();
    var ww = D.getDay();
    var ss = parseInt(D.getTime() / 1000);
    if (yy < 100) yy = "19" + yy;
    return GetLunarDay(yy, mm, dd);
  };
  CalendarHelper.GetAddDay = function (D, v) {
    var LSTR_ndate = D;
    var LSTR_Year = LSTR_ndate.getYear();
    var LSTR_Month = LSTR_ndate.getMonth();
    var LSTR_Date = LSTR_ndate.getDate();
    //处理
    var uom = new Date(LSTR_Year, LSTR_Month, LSTR_Date);
    uom.setDate(uom.getDate() + v); //取得系统时间的前一天,重点在这里,负数是前几天,正数是后几天
    return uom;
  }
  //是否除夕
  CalendarHelper.IsLastDayBeforeNewYearOfCN = function (D) {
    var strCurrDay = CalendarHelper.GetCNDate(D);
    var strNextDay = CalendarHelper.GetCNDate(CalendarHelper.GetAddDay(D, 1));
    //alert(strCurrDay+","+strNextDay);
    return strCurrDay.split('年')[0] != strNextDay.split('年')[0];
  };
  //是否春节
  CalendarHelper.IsNewYearOfCN = function (D) {
    var strCurrDay = CalendarHelper.GetCNDate(D);
    var strPrevDay = CalendarHelper.GetCNDate(CalendarHelper.GetAddDay(D, -1));
    //alert(strCurrDay+","+strPrevDay);
    return strCurrDay.split('年')[0] != strPrevDay.split('年')[0];
  };
  //------------------- End ----------------------
  var d1 = new Date();
  var d2 = new Date(2013, 1, 9); //注:此处相当于2013年2月9号
  var d3 = new Date(2013, 1, 10);
  var result = GetResult(d1) + GetResult(d2) + GetResult(d3);
  alert(result);
  function GetResult(D) {
    var y = D.getFullYear();
    var m = D.getMonth() + 1;
    var dd = D.getDate();
    var str = y + "年" + m + "月" + dd + "日";
    var isR = CalendarHelper.IsLastDayBeforeNewYearOfCN(D);
    var isN = CalendarHelper.IsNewYearOfCN(D);
    return "日期:"+str+","+ (isR?"是":"不是") + "除夕" + "," + (isN?"是":"不是") + "春节\n\n" ;
  }
</script>
</head>
<body>
</body>
</html>

希望本文所述对大家jQuery程序设计有所帮助。

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