C语言实现三子棋游戏(初级版)

软件发布|下载排行|最新软件

当前位置:首页IT学院IT技术

C语言实现三子棋游戏(初级版)

sugar high   2020-09-22 我要评论

本文着重为大家仔细讲解了C语言实现三子棋游戏初级版,文中代码实例讲解的非常细致,希望能够帮助到您,欢迎大家阅读和收藏


game.h

#include<stdio.h>
#include<stdlib.h>
#include<time.h>

#define ROW 3
#define COL 3

//声明函数
void InitBoard(char board[ROW][COL], int row, int col);
//打印棋盘
void PrintBoard(char board[ROW][COL], int row, int col);
//玩家下棋
void PlayerMove(char board[ROW][COL], int row, int col);
//电脑下棋
void ComputerMove(char board[ROW][COL], int row, int col);
//检测游戏输赢
char CheckWin(char board[ROW][COL], int row, int col);

game.c

#include "game.h"

//初始化棋盘
void InitBoard(char board[ROW][COL], int row, int col)
{
 int i = 0;
 for (i = 0; i < row; i++)
 {
 int j = 0;
 for (j = 0; j < col; j++)
 {
  board[i][j] = ' ';
 }
 }
}

//打印棋盘
void PrintBoard(char board[ROW][COL], int row, int col)
{
 int i = 0;
 for (i = 0; i < col; i++)
 {
 //打印数据
 int j = 0;
 for (j = 0; j < row; j++)
 {
  printf(" %c ", board[i][j]);
  if (j < row - 1)
  {
  printf("|");
  }
 }
 printf("\n");
 //打印分隔符
 if (i < row - 1)
 {
  for (j = 0; j < col; j++)
  {
  printf("---");
  if (j < col - 1)
  {
   printf("|");
  }
  }
  printf("\n");
 }

 }
}

//玩家走
void PlayerMove(char board[ROW][COL], int row, int col)
{
 int x = 0;
 int y = 0;

 printf("玩家走:>\n");

 while (1)
 {
 printf("请输入坐标:>");
 scanf("%d%d", &x, &y);
 if (x >= 1 && x <= row && y >= 1 && y <= col)
 {
  if (board[x - 1][y - 1] == ' ')
  {
  board[x - 1][y - 1] = '*';//落子
  break;
  }
  else
  {
  printf("该坐标已被占用,请重新输入\n");
  }
 }
 else
 {
  printf("坐标输入非法,请重新输入\n");
 }
 }

}

//电脑走
void ComputerMove(char board[ROW][COL], int row, int col)
{
 printf("电脑走\n");
 while (1)
 {
 int x = rand() % row;//0-2
 int y = rand() % col;//0-2
 if (board[x][y] == ' ')
 {
  board[x][y] = '#';
  break;
 }
 }

}

static int IsFull(char board[ROW][COL], int row, int col)
{
 int i = 0;
 int j = 0;
 for (i = 0; i < row; i++)
 {
 for (j = 0; j < col; j++)
 {
  if (board[i][j] == ' ')
  {
  return 0;
  }
 }
 }
 return 1;//没空格
}

//判断输赢
char CheckWin(char board[ROW][COL], int row, int col)
{
 int i = 0;
 //行判断
 for (i = 0; i < row; i++)
 {
 if (board[i][0] == board[i][1] && board[i][1] == board[i][2] && board[i][0] != ' ')
 {
  return board[i][0];
 }
 }
 //列判断
 for (i = 0; i < col; i++)
 {
 if (board[0][i] == board[1][i] && board[1][i] == board[2][i] && board[1][i] != ' ')
 {
  return board[0][i];
 }
 }
 //对角线判断
 if (board[0][0] == board[1][1] && board[1][1] == board[2][2] && board[1][1] != ' ')
 {
 return board[1][1];
 }
 if (board[0][2] == board[1][1] && board[1][1] == board[2][0] && board[1][1] != ' ')
 {
 return board[1][1];
 }

 //判断是否平局
 //判断期盼是否满了 键盘是否有空格
 if (IsFull(board, row, col) == 1)
 {
 return 'Q';
 }
 else
 return 'C';
}

test.c

#include "game.h"

void menu()
{
 printf("************************************\n");
 printf("*********   1. play  ***********\n");
 printf("*********   0. exit  ***********\n");
 printf("************************************\n");
}

//设计三子棋游戏

void game()
{
 char ret = 0;
 //存储数据的
 char board[ROW][COL] = { 0 };
 //数组应该初始化为空格
 InitBoard(board, ROW, COL);
 //打印棋盘
 PrintBoard(board, ROW, COL);

 //分析发现在玩游戏的过程中会出现的情况
 //1.玩家赢 - '*'
 //2.电脑赢 - '#'
 //3.平局了 - 'Q'
 //4.继续  - 'C'


 while (1)
 {
 PlayerMove(board, ROW, COL);
 //判断输赢
 ret = CheckWin(board, ROW, COL);
 if (ret != 'C')
  break;

 PrintBoard(board, ROW, COL);

 ComputerMove(board, ROW, COL);
 //判断输赢
 ret = CheckWin(board, ROW, COL);
 if (ret != 'C')
  break;

 PrintBoard(board, ROW, COL);
 }
 if (ret == '*')
 printf("玩家赢\n");
 else if (ret == '#')
 printf("电脑赢\n");
 else if (ret == 'Q')
 printf("平局\n");
 PrintBoard(board, ROW, COL);
}

int main()
{
 int input = 0;
 srand((unsigned int)time(NULL));
 do
 {
 menu();
 printf("请选择:>");
 scanf("%d", &input);
 switch (input)
 {
 case 1:
  game();
  break;
 case 0:
  printf("退出游戏\n");
  break;
 default:
  printf("选择错误\n");
  break;
 }
 } while (input);
 return 0;
}

输出结果:

更多有趣的经典小游戏实现专题,分享给大家:

C++经典小游戏汇总

python经典小游戏汇总

python俄罗斯方块游戏集合

JavaScript经典游戏 玩不停

java经典小游戏汇总

javascript经典小游戏汇总

Copyright 2022 版权所有 软件发布 访问手机版

声明:所有软件和文章来自软件开发商或者作者 如有异议 请与本站联系 联系我们