在这篇文章中小编为您讲解了关于python实现人性化显示金额数字实例内容，欢迎大家阅读。
我们在开发过程中，有时候需要把float，int型等数字作为金额类型数字显示会出现很多问题，比如float会显示成 965868.4599999，int型没有小数位等各种各样的问题。我们需要进行转换显示，才能保证阅读人性化。
方法一：
这里只贴上主要代码：
# 金额人性化
def humanized_amount(self, *args, **kwargs):
"""
金额人性化,保留二位小数，再进行人性化显示
compel强制二位，默认True，
"""
if not CheckData(self.__mark).is_int_or_float:
return {"code": "0001", "msg": "必须传入数字", "data": None}
else:
figure = float(self.__mark)
# 保留二位小数
figure = "{:.2f}".format(figure)
# 人性化显示
figure = "{:,}".format(float(figure))
if kwargs.get("compel", True):
# 进行处理，保留二位小数，如果不足二位补领
figure_list = figure.split(".")
if len(figure_list[1]) == 1:
figure += "0"
return figure
方法二：利用xToolkit库
安装方法：
pip install xToolkit -i http://pypi.douban.com/simple --trusted-host pypi.douban.com
xToolkit库是我自己封装的python内置库的一个扩展库.把python的datetime,string,list,dist，xthread等数据结构进行了功能的扩展。
使用方法比较简单，一行代码即可搞定
# 金额人性化,保留二位小数
xstring.dispose(3.0).humanized_amount(compel=False)
xstring.dispose("3.0").humanized_amount(compel=True)
xstring.dispose(37787841.902).humanized_amount(compel=False)
xstring.dispose("37787841.902").humanized_amount(compel=True)
xstring.dispose(378978989).humanized_amount(compel=False)
xstring.dispose("378978989").humanized_amount(compel=True)
>>3.0
>>3.00
>>37,787,841.9
>>37,787,841.90
>>378,978,989.0
>>378,978,989.00
实例扩展：
用python实现把数字人民币金额转换成大写的脚本程序
# -*- coding: utf-8 -*-
def Num2MoneyFormat( change_number ):
"""
.转换数字为大写货币格式( format_word.__len__() - 3 + 2位小数 )
change_number 支持 float, int, long, string
"""
format_word = ["分", "角", "元",
"拾","百","千","万",
"拾","百","千","亿",
"拾","百","千","万",
"拾","百","千","兆"]
format_num = ["零","壹","贰","叁","肆","伍","陆","柒","捌","玖"]
if type( change_number ) == str:
# - 如果是字符串,先尝试转换成float或int.
if '.' in change_number:
try: change_number = float( change_number )
except: raise ValueError, '%s can\'t change'%change_number
else:
try: change_number = int( change_number )
except: raise ValueError, '%s can\'t change'%change_number
if type( change_number ) == float:
real_numbers = []
for i in range( len( format_word ) - 3, -3, -1 ):
if change_number >= 10 ** i or i < 1:
real_numbers.append( int( round( change_number/( 10**i ), 2)%10 ) )
elif isinstance( change_number, (int, long) ):
real_numbers = [ int( i ) for i in str( change_number ) + '00' ]
else:
raise ValueError, '%s can\'t change'%change_number
zflag = 0 #标记连续0次数，以删除万字，或适时插入零字
start = len(real_numbers) - 3
change_words = []
for i in range(start, -3, -1): #使i对应实际位数，负数为角分
if 0 <> real_numbers[start-i] or len(change_words) == 0:
if zflag:
change_words.append(format_num[0])
zflag = 0
change_words.append( format_num[ real_numbers[ start - i ] ] )
change_words.append(format_word[i+2])
elif 0 == i or (0 == i%4 and zflag < 3): #控制 万/元
change_words.append(format_word[i+2])
zflag = 0
else:
zflag += 1
if change_words[-1] not in ( format_word[0], format_word[1]):
# - 最后两位非"角,分"则补"整"
change_words.append("整")
return ''.join(change_words)
print Num2MoneyFormat( 343.45 )
