在日常开发中，有时候需要把一个大列表分割为固定的小列表，再进行相关处理。下面来看看详细的分割方法：
>>> a = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9] >>> r = [[x] for x in a] >>> r [[0], [1], [2], [3], [4], [5], [6], [7], [8], [9]]
2.2.1 普通方法
In [17]: lst Out[18]: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9] In [18]: for i in range(0,len(lst),3): print(lst[i:i+3]) [0, 1, 2] [3, 4, 5] [6, 7, 8] [9]
2.2.2 改进方法
改进：用列表推导，结果都放到一个列表。
In [35]: lst Out[35]: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9] In [36]: b = [lst[i:i+3] for i in range(0,len(lst),3)] In [37]: b Out[37]: [[0, 1, 2], [3, 4, 5], [6, 7, 8], [9]]
2.2.3 lambda方法
In [10]: f = lambda a:map(lambda b:a[b:b+3],range(0,len(a),3)) In [11]: lst Out[11]: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9] In [12]: f(lst) Out[12]: [[0, 1, 2], [3, 4, 5], [6, 7, 8], [9]]
>>> a = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9] >>> l = len(a) # a 的长度 >>> l 10 >>> n = 5 # 平均 5 等份 >>> step = int(l/n) # 步长 >>> step 2 >>> b = [a[i:i+step] for i in range(0, l, step)] >>> b [[0, 1], [2, 3], [4, 5], [6, 7], [8, 9]]
【1】https:
